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Oracle Database 12c SQL

Question No: 1

Examine the structure of the invoice table.

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Which two SQL statements would execute successfully? A)

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B)

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C)

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D)

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  1. Option A

  2. Option B

  3. Option C

  4. Option D

Answer: C

Question No: 2

Which statement is true regarding the INTERSECT operator?

  1. It ignores NULL values

  2. The number of columns and data types must be identical for all SELECT statements in the query

  3. The names of columns in all SELECT statements must be identical

  4. Reversing the order of the intersected tables the result

Answer: B Explanation:

INTERSECT Returns only the rows that occur in both queries’ result sets, sorting them and removing duplicates.

The columns in the queries that make up a compound query can have different names, but the output result set will use the names of the columns in the first query.

Question No: 3

Which task can be performed by using a single Data Manipulation Language (OML) statement?

  1. adding a column constraint when inserting a row into a table

  2. adding a column with a default value when inserting a row into a table

  3. removing all data only from one single column on which a unique constraint is defined

  4. removing all data only from one single column on which a primary key constraint is defined

Answer: D

Question No: 4

You want to display the date for the first Monday of the next month and issue the following command:

SQLgt;SELECT TO_CHAR(NEXT_DAY(LAST_DAY(SYSDATE),#39;MON#39;), #39;dd quot;is the first

Monday forquot;fmmonth rrrr#39;) FROM DUAL; What is the outcome?

  1. It executes successfully and returns the correct result.

  2. It executes successfully but does not return the correct result.

  3. It generates an error because TO_CHAR should be replaced with TO_DATE.

  4. It generates an error because rrrr should be replaced by rr in the format string.

  5. It generates an error because fm and double quotation marks should not be used in the format string.

Answer: A Explanation:

  • NEXT_DAY(date, #39;char#39;): Finds the date of the next specified day of the week (#39;char#39;) following date. The value of char may be a number representing a day or a character string.

  • LAST_DAY(date): Finds the date of the last day of the month that contains date

The second innermost function is evaluated next. TO_CHAR(#39;28-OCT-2009#39;, #39;fmMonth#39;) converts the given date based on the Month format mask and returns the character string October. The fm modifier trims trailing blank spaces from the name of the month.

Question No: 5

Which statements are true? (Choose all that apply.)

  1. The data dictionary is created and maintained by the database administrator.

  2. The data dictionary views can consist of joins of dictionary base tables and user-defined tables.

  3. The usernames of all the users including the database administrators are stored in the data dictionary.

  4. The USER_CONS_COLUMNS view should be queried to find the names of the columns to which a constraint applies.

  5. Both USER_OBJECTS and CAT views provide the same information about all the objects that are owned by the user.

  6. Views with the same name but different prefixes, such as DBA, ALL and USER, use the same base tables from the data dictionary

Answer: C,D,F

Question No: 6

Examine the business rule:

Each student can take up multiple projects and each project can have multiple students.

You need to design an Entity Relationship Model (ERD) for optimal data storage and allow for generating reports in this format:

STUDENT_ID FIRST_NAME LAST_NAME PROJECT_ID PROJECT_NAME PROJECT_TASK

Which two statements are true in this scenario?

  1. The ERD must have a1:M relationship between the students and projects entitles.

  2. The ERD must have a M:M relationship between the students and projects entities that must be resolved into 1:M relationships.

  3. STUDENT_ID must be the primary key in the STUDENTS entity and foreign key in the projects entity.

  4. PROJECT_ID must be the primary key in the projects entity and foreign key in the STUDENTS entity.

  5. An associative table must be created with a composite key of STUDENT_ID andPROJECT_ID; which is the foreign key linked to theSTUDENTSandPROJECTSentities.

Answer: D,E

Question No: 7

View the Exhibit and examine the data in ORDERS and ORDER_ITEMS tables.

You need to create a view that displays the ORDER ID, ORDER_DATE, and the total number of items in each order.

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Which CREATE VIEW statement would create the view successfully?

  1. CREATE OR REPLACE VIEW ord_vu (order_id,order_date) AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id) quot;NO OF ITEMSquot;

    FROM orders o JOIN order_items i ON (o.order_id = i.order_id)

    GROUP BY o.order_id,o.order_date;

  2. CREATE OR REPLACE VIEW ord_vu

    AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id) quot;NO OF ITEMSquot;

    FROM orders o JOIN order_items i ON (o.order_id = i.order_id)

    GROUP BY o.order_id,o.order_date;

  3. CREATE OR REPLACE VIEW ord_vu

    AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id) FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY o.order_id,o.order_date;

  4. CREATE OR REPLACE VIEW ord_vu

AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)ll’ NO OF ITEMS#39; FROM orders o JOIN order_items i

ON (o.order_id = i.order_id) GROUP BY o.order_id,o.order_date WITH CHECK OPTION;

Answer: B

Question No: 8

The following are the steps for a correlated subquery, listed in random order:

  1. The WHERE clause of the outer query is evaluated.

  2. The candidate row is fetched from the table specified in the outer query.

  3. The procedure is repeated for the subsequent rows of the table, till all the rows are processed.

  4. Rows are returned by the inner query, after being evaluated with the value from the candidate row in the outer query. Identify the option that contains the steps in the correct sequence in which the Oracle server evaluates a correlated subquery.

A. 4,2,1,3

B. 4,1,2,3

C. 2,4,1,3

D. 2,1,4,3

Answer: C

Question No: 9

Which three tasks can be performed using SQL functions built into Oracle Database? (Choose three.)

  1. Combining more than two columns or expressions into a single column in the output

  2. Displaying a date in a nondefault format

  3. Substituting a character string in a text expression with a specified string

  4. Finding the number of characters in an expression

Answer: B,C,D

Question No: 10

View the Exhibits and examine the structures of the costs and promotions tables? 1.

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2.

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Evaluate the following SQL statement: SQLgt; SELECT prod_id FROM costs

WHERE promo_id IN (SELECT promo_id FROM promotions WHERE promo_cost lt; ALL

(SELECT MAX(promo_cost) FROM promotions GROUP BY (promo_end_datepromo_ begin_date)));

What would be the outcome of the above SQL statement?

  1. It displays prod IDs in the promo with the lowest cost.

  2. It displays prod IDs in the promos with the lowest cost in the same time interval.

  3. It displays prod IDs in the promos with the highest cost in the same time interval.

  4. It displays prod IDs in the promos with cost less than the highest cost in the same time interval.

Answer: D

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